Question

Solve. x2 + 8x + 25 = 0

Answer 1

Use the quadratic formula to solve.

x = (-b+-sqrt(b^2-4ac))/(2a)


x = (-(8)+-sqrt((8)^2-4(1)(25)))/(2(1))


x = (-8+-sqrt(64-(100)))/(2)


x = (-8+-sqrt(-36))/2


x = (-8+sqrt(-36))/2 or x = (-8-sqrt(-36))/2


x = (-8+6*i)/2 or x = (-8-6*i)/2

x = -4+3i or x = -4-3i


So the solutions are x = -4+3i or x = -4-3i where i = sqrt(-1)

Answer 2

you could try doing thrugh the trial and error method of solving quadratic equations
x +3 l +3x
x +5 l +5x
x^2 +25 l + 8x

Answer 3

so factors are (x+3)(x+5)