Question

How do I solve this:
ln(x+1)-ln(x-1)=3

Answer 1

\[\begin{align}
ln\left(\frac{x+1}{x-1}\right)&=3\\
\frac{x+1}{x-1}&=e^3\\
x+1&=e^3 x - e^3\\
e^3+1&=(e^3-1)x\\
x&=\frac{(e^3+1)}{(e^3-1)}\\
\end{align}\]

Answer 2

Thank you!