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Mathematics
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Simplify (a^5b^2 - a^3b^4)/(a^2b + ab^2)
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a^2b(a-b)
How did you get that?
So are you left with 1/ab^2?
take 'a^3b^2' common in numerator and 'ab' common in denominator.\[a ^{3}b ^{2}(a ^{2} - b ^{2}) / ab(a + b)\]\[a ^{2}b(a -b)(a+b)/(a+b)\]\[a ^{2}b(a -b)\]\[a ^{3}b - a ^{2}b ^{2}\]
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@ jazy: Then I guess I misread your post. I'm confused, everyone is getting a different answer.
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