Question

(7x^2 - 21x)/(x^2 - 7x - 18)
divided by (x - 3)/(x - 9)

Answer 1

\[[(7x^2-21x)/(x^-7x-18)]/[(x-3)/(x-9)] = [(7x(x-3))/((x-9)(x+2)]*[(x-9)/(x-3)] = (7x)/(x+2)\]

Answer 2

I think you misread the question. In the denominator of the first fraction it is
x^2 - 7x - 18, not x(-7x) - 18...

Answer 3

\[x ^{2}-7x-18\]