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Mathematics 19 Online
OpenStudy (anonymous):

Help

OpenStudy (anonymous):

\[p ^{1/9}p ^{11/18}p ^{1/2}\div(p ^{34})^{-1/9}\]

OpenStudy (cwtan):

using a^m x a^n=a^mn and a^m/a^n=a^m-n The answer is p with power (1/9)(11/18)(1/2)-34(-1/9)

OpenStudy (anonymous):

I dont understand

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