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Mathematics
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OpenStudy (anonymous):
what is a factored form of 16x^2 -1
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OpenStudy (auctoratrox):
(4x+1)(4x-1)
Parth (parthkohli):
\(1 = 1^2, right?\)
So,
\[\Large \color{purple}{\rightarrow 16x^2 - 1^2 }\]
\[\Large \color{purple}{\rightarrow (4x)^2 - 1^2 }\]
\[\Large \color{purple}{\rightarrow (4x + 1)(4x - 1) }\]
Parth (parthkohli):
Using the law \(a^2 - b^2 = (a + b)(a - b)\)
OpenStudy (anonymous):
The anwsers are more complex then that idk how to do their version of it...
OpenStudy (auctoratrox):
whats the whole question?
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OpenStudy (anonymous):
What is the factored form of 8x^3 + 1 sorry i typed in the wrong question......my bad.
OpenStudy (auctoratrox):
that's a difference of cubes, so we get a^3 + b^3 = (a + b)(a^2 – ab + b^2)
OpenStudy (anonymous):
(2x+1)(4x^2-2x+1)
Parth (parthkohli):
\[\Large \color{purple}{\rightarrow 8x^3 + 1^3 }\]
\[\Large \color{purple}{\rightarrow (2x)^3 + 1^3 }\]
\[\Large \color{purple}{\rightarrow (2x+ 1)(2x - 2x + 1) }\]
OpenStudy (auctoratrox):
(2x+1)(4x^2 -2x+1)
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Parth (parthkohli):
Oh yes, my bad.
OpenStudy (anonymous):
Thanks you guys it was alot of help!
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