Question

What is the solution to the equation 49^x =sqrt(7)^ (2x + 6)?

a. x = 3
b. x = –3
c. x = 1
d. x = –1

Answer 1

\[49^x=\sqrt{7}^{2x+6}\]\[7^{2x}=7^{x+3}\]
\[2x=x+3\]
\[x=3\]

Answer 2

\[49^x =\sqrt{7}^{2x + 6}\]\[\sqrt7^{4x} =\sqrt{7}^{2x + 6}\]4x=2x+6
2x=6
x= 6/2 =3

Answer 3

why 4x?

Answer 4

\[49^x = 7^{2x} = \sqrt7^{2(2x)} = \sqrt7^{4x}\]

Answer 5

oh i get it thanks!