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What is the solution to the equation log 2 x – log 2 4 = 5? a. x = 2 b. x = 4 c. x = 32 d. x = 128
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\[\large log_ma - log_mb = log_m(a/b)\] Use this to club together the two terms in LHS, and then take anti-log both sides.
ok so its log 2 x/4 = 5 now?
Yes!
so what else?
how do u get the answer?
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\[log_2x-log_24 = 5\]\[log_2\frac{x}{4} = 5\]\[\frac{x}{4} = 2^5\]\[\frac{x}{4} = 32\]Can you solve x?
why 2^5
because:|dw:1336895172796:dw|
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