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OpenStudy (anonymous):
if 0 = (16x-x) does it mean x=1/16?
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OpenStudy (dumbcow):
no 16x-x = 15x ...x = 0
OpenStudy (dumbcow):
0 = 16x - 1 --> x = 1/16
OpenStudy (lgbasallote):
the dumbcow is right :)
OpenStudy (anonymous):
\[\log _{2}x-\log _{4}x = -2 \] how then? :/
OpenStudy (lgbasallote):
tricky...you need to use change-of-base formula..are you familiar with that?
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