In a dog show, 20% of the dogs are eliminated each day. If the competition starts with 2,000 dogs, to the nearest integer, how many dogs will be present at the start of the 5th day?
a. 259
b. 480
c. 819
d. 1,229

Confused....

Question

In a dog show, 20% of the dogs are eliminated each day. If the competition starts with 2,000 dogs, to the nearest integer, how many dogs will be present at the start of the 5th day?  
a. 259
b. 480
c. 819
d. 1,229

Confused....

anonymous · Answer

by eliminated do you mean killed? because that makes this question so much more exciting!

anonymous · Answer

haha...

anonymous · Answer

so we have a geometric sequence, with the initial value = 2000

common ratio = 100% - 20% = 80% = 0.8

Un = ar^(n-1)
n=5 in this case
$$2000 \times (0.8)^4$$

anonymous · Answer

have you done geometric sequences before?

anonymous · Answer

yes

anonymous · Answer

so wait u have to subtract 100-20?

anonymous · Answer

so if we do that tahn its 819.2 so c?

anonymous · Answer

$$2000 \times (1 \div 5)^{4}$$

since its the 5th day and the dogs haven't been eliminated on the fifth day

anonymous · Answer

oh damn 

$$2000 \times (4 \div 5)^4$$

i din't read the question carefully lol

anonymous · Answer

is ti c?