Question

A particle P moves in a straight line. It starts from a point O on the line with velocity 1.8 m s^−1. The
acceleration of P at time ts after leaving O is 0.8t^−0.75m s^−2. Find the displacement of P from O when t = 16.

Answer 1

\[
a(t) = 0.8t^{−0.75}\\
v(t)=0.32 t^{0.25} + 1.8 \\
s(t) = 0.256 t^{1.25}+1.8 t
\]
All you have to do is compute s(15)