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OpenStudy (anonymous):
ʃ(sinx) ˄6cosxdx
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OpenStudy (anonymous):
substitution: u=sinx, du=cosxdx so the integral is now: ʃu˄6du
OpenStudy (anonymous):
ʃu˄6du=1/7u˄7 +C back to previous variable: 1/7sinx˄7 +C
OpenStudy (anonymous):
good work
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