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Mathematics 21 Online
OpenStudy (anonymous):

ʃ(sinx) ˄6cosxdx

OpenStudy (anonymous):

substitution: u=sinx, du=cosxdx so the integral is now: ʃu˄6du

OpenStudy (anonymous):

ʃu˄6du=1/7u˄7 +C back to previous variable: 1/7sinx˄7 +C

OpenStudy (anonymous):

good work

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