Question

Write a slope-intercept equation for a line parallel to the line x + 7y = 3 which passes through
the point (–14, 6).

Answer 1

if it is parralel it will have the same slope so first we find the slope of the original line x+7y=3 so we would rearrange this to \[(3-x)/7\]

Answer 2

so the equation would be\[(3/7)-(x/7)=y \]
and the slope would be -(1/7)x

Answer 3

so now using point slope form we can derive the new equation\[x-x _{1} =m(y-y _{1})\]