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If you own 6 hats and are taking four on vacation. In how many ways can you choose 4 hats from the six?
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The formula for \(6C4\) is what you want\[{6! \over {4!(6-4)!}}\]
so it would be using combination then?
Yes.
thanks!
You're welcome.
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So if doing the problem "3 bananas are to be selected froma group of 9. In how many ways can this be done?" Would you use nPr or nCr?
That would also be combinations.
You would use nCr. When the three bananas are selected the way the bananas are arranged does not matter. Therefore you are not dealing with a permutation
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