Question

The figure below shows line AB parallel to line CD. Segment EF is parallel to segment GH.



What is the value of x?

Answer 1

\(\angle \text{EFC} \cong \angle \text{HGB} \)
So, \(m \angle \text{EFC} = m \angle \text{HGB} \).

Set up the equation and solve for \(x\).

Answer 2

\[
\quad m \angle \text{EFC} = x + 5, \\
\quad m \angle \text{HGB} = 2x - 60 \\ ~\\
\begin{split}
m \angle \text{EFC} &= m \angle \text{HGB} \qquad & \text{Substitute}\\
x + 5 &= 2x - 60 & \text{Solve for } x.
\end{split} \]

Answer 3

lol... my firewall blocks the word xxxx.jpg :)