Question

Area of small / Area of Large
small rectangle: length=x and width=x + 3
large rectangle: length=3x and width=x^2 + 7x + 12

Answer 1

Area of a rectangle is length time width so the area of the small rectangle compared to the large rectangle is:

[(X)(X+3)]/[(3X)(X^2+7X+12)]

Answer 2

ok I did that part and got:
3(x^2 + 7x + 12) = 3x(x + 3)
3x^2 + 21x + 24 = 3x^2 + 9x
x^3 + 4x^2 + 3x
But how do you simplify that?
My options are:
3(x + 4)
x + 3 /x^2 + 7x + 12
3x /x + 4
1 /3x + 4

Answer 3

\( \frac{x(x+3)}{3x(x^2+7x+12)} = \frac{(x+3)}{3(x+4)(x+3)}=\frac{1}{3(x+4)}\)

Answer 4

Thank you so much!