The numerator and denominator of a fraction are in the ratio of 1 to 3. If the numerator and denominator are both increased by 2, the fraction is now equal to 3/4.
If n = the numerator and d = the denominator, which of the following systems of equations could be used to solve the problem?
3n = d and 4n + 8 = 3d + 6
3n = d and 4n + 6 = 3d + 5
n = 3d and 3n + 6 = 2d + 4
n = 3d and 3n + 6 = 4d + 8

Question

The numerator and denominator of a fraction are in the ratio of 1 to 3. If the numerator and denominator are both increased by 2, the fraction is now equal to 3/4.
If n = the numerator and d = the denominator, which of the following systems of equations could be used to solve the problem?
3n = d and 4n + 8 = 3d + 6
3n = d and 4n + 6 = 3d + 5
n = 3d and 3n + 6 = 2d + 4
n = 3d and 3n + 6 = 4d + 8

anonymous · Answer

im wanting to say the top one