Ask your own question, for FREE!
Mathematics 21 Online
OpenStudy (anonymous):

factor by grouping. (PLEASE HELP ME) 24x^2 - 20xy +30 xy -25y^2

OpenStudy (pfenn1):

\[24x^2-20xy+30xy-25y^2=24x^2+10xy-25y^2\]

OpenStudy (pfenn1):

To factor this, we want something like \[(ax+b)(cx+d)\]where\[ac=24\]\[bd=-25\]\[ad+bc=10\]

OpenStudy (pfenn1):

Factors a and c could be 1, 2, 3, 4, 6, 12, or 24 Factors b and d could be 1, 5, 25, -1, -5, -25

OpenStudy (pfenn1):

Let's try to use 4 and 6 for a and c\[(4x+b)(6x+d)\] what could b and d be so that \[bd=-25\]and \[4d+6c=10\]

OpenStudy (kinggeorge):

Factor by grouping: \[24x^2+30xy-20xy-25y^2\]\[6x(4x+5y)-5y(4x+5y)\]\[(6x-5y)(4x+5y)\]

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!