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Product of (1+i)(1-2i)
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can you FOIL binomials?
yes thats all i do?
yes... that's it. then simplify.
oh ok thank you
yw
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ok that didnt work
what did you get?
remember that \(i^2 = -1\)
2i^2-i+1
ahh
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right...
and it should be \(-2i^2 - i + 1\) coz \(-2i \times i = 2i^2\) sorry dp :p
hahaha
that's \(-2i \times i = -2i^2\)
is the answer 1+4i?
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i really have no idea lol
how did you get that? it's \(-2i^2 - i + 1\) like i said \(i^2 = -1\) so \((-2)(-1) - i +1 \)
oh. lol i see
i was just guessing
i do that often trust me
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