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Mathematics
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Evaluate. 9!/6!4! 14 21 42
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\[\frac{9!}{6!4!}\] We know that \[n!=n.(n-1)!\] \[\frac{9.8.7.6!}{6!4!}\] Can you solve now?
\[\Large \frac{(9)(8)(7)(6)(5)(4)(3)(2)(1)}{(6)(5)(4)(3)(2)(1) \times (4)(3)(2)(1)}\] cancel all that an be
can be*
21 ;) thanks
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