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Mathematics 11 Online
OpenStudy (anonymous):

What is the range of the function y = x2 + 1? all real numbers x ≥ 0 y ≥ 0 y ≥ 1

OpenStudy (anonymous):

since this is a parabola opening upwards, the lowest y value is at your vertex and it ranges to postitive infinity.

OpenStudy (anonymous):

do know where your vertex is?

OpenStudy (anonymous):

Simply plugin x= 0 and find your y- value Then plugin x = -3 and find your y-value then plugin x = 3 and find your y-value. You will observe something specific about y

OpenStudy (anonymous):

@mathboy2 , no

OpenStudy (anonymous):

y=1 because 0^2+1=1

OpenStudy (anonymous):

Yes. So give me any x-value for which you find y to be lesser than one . Can you find any such x- value??

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