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Mathematics 7 Online
OpenStudy (anonymous):

How many distinct ways can 3 red flags, 2 blue flags, 2 green flags and 4 yellow flags be arranged in a row

OpenStudy (kropot72):

The number of permutations is as follows: \[\frac{11!}{3!2!2!4!}\]

OpenStudy (anonymous):

ahh okay, thanks i was having trouble setting the question up but now i get it

OpenStudy (kropot72):

Good work! :)

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