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Find the first, fourth, and eighth terms of the sequence. A(n)=-5 x 2^n-1. HELP PLEASE???????????
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replace \(n\) by 1 for the first term, bet \[A(1)=-5\times 2^{1-1}=-5\times 2^0=-5\] (since \(2^0=1\))
now replace \(n\) by 4 and get \[A(4)=-5\times 2^{4-1}=-5\times 2^3=-5\times 8=-40\]
your on your own with the last one, but the procedure is the same as for the first two
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