A spinner is divided into 10 equal segments. Each segment is numbered 1 - 9 and one segment is labeled with "Free Spin." Isaiah spins the spinner ten times and gets a number eight times. What is the probability that he will get a number on the eleventh try? A. 0% B. 100% C. 10% D. 90%
This question is not a direct question, it's more like a confusing question. What has happened doesn't affect the probability of an event that will happen. Here's the hint for you.
What am I supposed to do to solve this?
\(\Large \color{midnightblue}{\rightarrow P(Event) = {\text{Preferred number of outcomes} \over \text{Total number of outcomes}} }\)
What do you think now?
would it be 9/10?
Noooo
mmmmmm
You want one number, and total segments are 10. 1/10 = 10% is the probability.
ohhhhh ok!! The answer is C
Yes...
ok Thank you soooo much! I really appreciate ur help :D
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