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In circle A shown below, m arc BC is 61° and m Arc EF is 76°. What is m∡FDE? Answer 76° 38° 30.5° 68.5°
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68.5° === The angle formed when two chords intersect within a circle is equal to 1/2 the sum of the measures of the arc the angle cuts off and that which the the angle vertical to the original angle intercepts. m<FDE = 1/2( Arc BC + Arc 76) m<FDE = 1/2 (61 + 76) m<FDE = 137/2 = 68.5 degrees
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