Question

how do i solve for x?
3^(2x-1) = 1/9

Answer 1

\[3^{2x-1} = 1/9\]
\[\Large 3^{2x-1} = 9^{-1}\]
\[\Large 3^{2x-1} = 3^{-2}\]
2x-1=-2
x=?

Answer 2

thanks