Question

How do i solve for x?
(1/4)^(x+1) = 8^(2x+3)

Answer 1

\[(1/4)^{x+1} = 8^{2x+3}\]
\[4^{-1(x+1)} = 8^{2x+3}\]
\[\Large 2^{-2(x+1)} = 2^{3(2x+3)}\]
-2(x+1)=3(2x+3)
Solve

Answer 2

still need help?

Answer 3

nope, thanks anyways

Answer 4

:)

Answer 5

does x = -5/8