Question

Triangle ABC with AD bisecting angle BAC, and AE is congruent to ED (both line segments). The question is asking for me to prove that AE/AC = BD/BC.
The picture has an isoceles triangle with "A" at the top and the base being "B" on the left, and "C" on the right. The bisector is AD and "D" is between "B" and "C" on the base of this triangle. There is also a segment drawn from "D" to "E". a point on the AC segment on the right side of the triangle