Question

What is the sum of the measures of the interior angles of a regular polygon where a single exterior angle measures 72°?

Answer 1

Number of sides \(= \frac {360} {72} = 5\)

Answer 2

Now, use \((2n-4)\times 90 = 540^\circ , n = 5\)

Answer 3

just wondering where does \[\large \frac{360}{72}\] come from @FoolForMath a formula?

Answer 4

Sum of all exterior angles of any polygon is \(360^\circ \). In regular they are equal.

Answer 5

i see thanks