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Use system oof equation. How many liters each of 15% acid and 33% acid should be mixed to get 120 liters of 21% acid?
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im guessing the system would be using % acid and % water hmm
yes
this will be your equation x L 15% acid + y L 33% acid = 120 L 21 % acid x L 85% water + y L 67% water = 120 L 79% water 0.15x + 0.33y = 25.2 0.85x + 0.67y = 94.8 i'll leave the rest to you :D
okay thanks
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