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What is the sum of the series below? 6 ∑(7i-2) i=1
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135
how did you get that answer?
evaluate for each value of i and add
(7-2)+(14-2)+(21-2)+(28-2)+(35-2)+(42-2)
6 ∑(7i-2) = (7(1) - 2) + (7(2) - 2) + (7(3) - 2) + (7(4) - 2)+ (7(5) - 2) + (7(6) - 2) i = 1
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there is a formula you can use to calculate this but don't expect to have to do this very much so the formulas are more of a novelty usually at least they were for me
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