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-Factor Out The GCF Of The Polynomial x^3-4x^2-21x
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Is there anything besides x that you can factor out?
What is left is easy to factor. Do the first step by factoring x out.
I will do the first step for you. \[x^3-4x^2-21x =x( x^2-4x-21)\]
\[ x^2 - 4 x - 21= (x -?)( x+?) \]
So How Do You Factor Out The Rest?
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(x-7)(x+3)
Can You Exsplain How You Got It?
x1+x2=-(-4) x1.x2=-21
sum 4 and product 21
(x -7)(x + 3) = x·x -x·7 + 3·x +-21 First Outer Inner Last = x^2 -4x -21
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