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solve for x sqrt (x) +3 = 1/2 (x+3)
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\[\sqrt{x} + 3 = 1/2 (x+3)\]
dont see how that works.
where did the sqrt of x go from the initial problem?
i can multiply by 2 leaving 2sqrt (x) +6 = x +3 then subtract 3 leaving 2sqrt (x) +3 = x
do i then square both sides to get 4x+9=x^2
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crap... sorry i coppied the problem wrong... the answer is x=9
okay going back to 2sqrt(x)+3=x solve for x
how does x =9?
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