Question

Can you guys please check my homework solutions? Please, I'm begging you guys.....

Answer 1

questions 1 2 3 are correct questions 4, 5, 6 are incorrect

Answer 2

you need to practise getting a common denominator. thats what is different about 4,5,6

Answer 3

\[\frac{x+3}{x^2}+\frac{2}{3x} = \frac{3(x+3)}{3x^2} + \frac{2x}{3x^2} = \frac{5x+9}{3x^2}\]

Answer 4

\[\frac{4}{x-8} + \frac{1}{x-4} = \frac{4(x-4)}{(x-8)(x-4)} + \frac{x-8}{(x-8)(x-4)} = \frac{5x-24}{(x-8)(x-4)}\]

Answer 5

@Korra you see?