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Which celebrity do you get from sin(b)/tan(b)?
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celebrity?
Yes, sounds like the answer of sin(b)/tan(b)
\[\large \tan(b)= \frac{\sin(b)}{\cos(b)}\] Therefore: \[\Large \frac{\sin(b)}{\tan(b)}= \frac{\sin(b)}{ \frac{\sin(b)}{\cos(b)}}= \sin(b) \times \frac{\cos(b)}{\sin(b)}= \cos(b)\]
LoL
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