Question

A.s Problem :
____________
Find A.s if the sum of all terms starting from the second term is (-36) and the sum of all terms except the last term is Zero and the difference between the sixth term and the tenth term is equal to 16.
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Answer 1

No LaTex, not interested.

Answer 2

@experimentX :If u have time :)

Answer 3

let, \( n\) be the number of terms!!
given, \( S_n - a = -36 \implies \frac{n (a+l)}{2} - a = -36\)
or \( \frac{n (2a+(n-1)d)}{n} - a = -36\) -------- 1
\( S_n - l = 0 \implies \frac{n (a+l)}{2} - l = 0\)
or, \frac{n(2a+(n-1)d)}{n} - a - (n-1)d = 0\) -------- 2 <-- also it implies that AP must be
And
\( a + (5-1)d - (a + (10-1)d = 16 \) ---- 3

3 unknown variables and three equations ... it should be solveable!!

Answer 4

Ah ... that n in 1 down there is supposed to be 2

Answer 5

aha ,I got it :) ,TYSM for your time :) @experimentX

Answer 6

yw ..