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does x= 1/8 for (1/8)^(2x-5) = 4^(x+8)
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plug x = 1/8 into the equation and see ; (1/8)^ (-19/4) = 19483 4 ^(8 1/8) = 77935 no
No i need to find what x= though.
How do you do it right
take logs of both sides (2x - 5) log 1/8 = (x+8) log 4 (2x-5) ------ = log 4 / log 1/8 = -2/3 (x+8) 2x - 5 = -(2/3)x - 16 /3 6x - `5 = -2x - `6 8x = -1 x = -1/8
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