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OpenStudy (anonymous):
Solve the equation for x and round your answer to the nearest hundreth. 5 = ln(x + 1)
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OpenStudy (campbell_st):
raise each side as powers of e use the log/power law \[e^{\ln(a)} = a\] the equation is now \[e^5 = x + 1\] \[x = e^5 -1\] just evaluate
OpenStudy (anonymous):
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