Mathematics
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OpenStudy (anonymous):
If y varies directly with x and y=7 and when x=56, then find.
the constant of variation k
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OpenStudy (diyadiya):
y varies directly with x means y = kx
where k is proportionality constant
OpenStudy (diyadiya):
so here
y=7 & x =56
substitute the value of y & x in the equation
\[\Large y =kx\]
can you find it ?
OpenStudy (diyadiya):
@rebecca1233 can you?
OpenStudy (anonymous):
so i times ?
OpenStudy (anonymous):
392?
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OpenStudy (diyadiya):
\[\Large y=kx\]\[7= k \times 56\]to find k we divide both sides by 56
What do you get now?
OpenStudy (anonymous):
0.125
OpenStudy (diyadiya):
Right :)
OpenStudy (anonymous):
so thats the answer ?
OpenStudy (diyadiya):
Yeah
7/56=1/8=0.125
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OpenStudy (anonymous):
thank you can you help me with a few more please
OpenStudy (diyadiya):
Will try :)
OpenStudy (anonymous):
If y varies directly with x and y=7 and when x=56, then find.
the value of when x=4
OpenStudy (diyadiya):
So its the same question
y varies directly with x
so what will be the equation ?
OpenStudy (anonymous):
7/4?
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OpenStudy (anonymous):
x=ky
OpenStudy (diyadiya):
Nope ,
y varies directly with x
so
y=kx
if its x varies directly with y it will be x=ky
understood ?
OpenStudy (anonymous):
yes
OpenStudy (diyadiya):
y = kx
7=k*56
k=7/56 =1/8
OpenStudy (diyadiya):
For these type of questions ,First step is to find the value of k
ok?
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OpenStudy (anonymous):
ok
OpenStudy (diyadiya):
So now we have k =1/8 (or 0.125)
consider the same equation
y=k*x
here x = 4 & k =0.125
so what is y = ?
OpenStudy (anonymous):
u divide right ?
OpenStudy (diyadiya):
y = k* x
which all values you have ?
OpenStudy (diyadiya):
ok tell me what are we trying to find ..?
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OpenStudy (anonymous):
idk it says the value of when x=4
OpenStudy (diyadiya):
you probably read the question wrong ,it will be ' the value of y when x=4"
OpenStudy (diyadiya):
so we are finding y here
OpenStudy (anonymous):
not on my paper it doesnt say y or anything
OpenStudy (diyadiya):
it might be printing mistake
" the value of when x=4 " doesn't make any sense
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OpenStudy (diyadiya):
do you have the answer ?
OpenStudy (anonymous):
hno
OpenStudy (anonymous):
how do you do this
OpenStudy (anonymous):
give the equation of the line
OpenStudy (anonymous):
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