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find an appropriate solution (to 4 decimal places) for each equation 3^x+2=5
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3^x = 5 -2 3^x = 3^1 ->x = 1
wouldnt that make it if plug 1 in for x 3^3=5
should be a number i have to round to 4 decimal places
I probably a general instruction for all problems!
what do you mean by that
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In this case, luckily the result is even, but most of other cases it's not!
how can x=1
put it back in original problem it comes out 3^3=5
That's the whole entire solution already!
that would be 27=5
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