Question

solve, log2(a^2+3)+log2 4=4
please show work and steps.

Answer 1

\[\log_{2} (a ^{2}+3)+\log_{2} 4=4\]
\[\log_{2} (a ^{2}+3)+\log_{2} 2^{2}\]
\[\log_{2} (a ^{2}+3)+2=4\]
\[\log_{2} (a ^{2}+3)=2\]
\[\log_{2} (a ^{2}+3)=\log_{2} 2^{2}\]
then,\[a ^{2}+3=2^{2}\]
\[a ^{2}=1\]
hence, a=1 or a=-1

Answer 2

thanks man super help :)