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solve by factoring: x^2-6X-72=0
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Notice that 72 is 12*6, and 6-12=-6
x^(2)-6x-72 For a polynomial of the form x^(2)+bx+c, find two factors of c (-72) that add up to b (-6). In this problem 6*-12=-72 and 6-12=-6, so insert 6 as the right hand term of one factor and -12 as the right-hand term of the other factor. (x+6)(x-12)
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