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Find the slope of the line tangent. y=[3x^3-4x^2+5]/[2x^2]; (2, (13/8))
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divide
3/2x-2+(5/2x^2) now what?
take the derivative and replace x by 2
how does the derivative look?
do you know how to find the derivative of \[y=\frac{3}{2}x-2+\frac{5}{2x^2}\]?
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i can write it if you like
yes please
\[y'=\frac{3}{2}-\frac{5}{x^3}\]
is the final answer 7/8?
i don't know i didn't do it did you replace \(x\) by 2?
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oh yes, you are right!
thanks!
yw
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