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Multiplicative inverse of 4+3i
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i believe multiplicative inverse are the values that will make it one...
but it may be not the case in complex numbers..i cannot seem to recall
It is the same in the complex numbers. So you want to find a complex number a+bi such that \[(4+3i)(a+bi)=1\]
I've got to leave, but look at the complex conjugate \(x=4-3i\) to get a real number, and then see what you need to get 1.
lol
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