Question

solve log3(2c)=-2

Answer 1

\[\huge \log_2 (2c) = -2?\]

Answer 2

yes

Answer 3

change to exponential form \[3^{-2} = 2c\]

Answer 4

no but its a 3

Answer 5

k, then what after exponential form

Answer 6

what is \(\large 3^{-2}\)?

Answer 7

-9 or is it 1/9

Answer 8

1/9

so \[\Large \frac{1}{9} = 2c\] now divide both sides by 2

Answer 9

yes but how would you divide a fraction by 2. Is the answer \[1/9/2\]

Answer 10

\[\frac{\frac{1}{9}}{2} = \frac{1}{9} \times \frac{1}{2}\] multiply by reciprocal remember?