Question

What is the equation of the line that passes through the point (1, 6) and has a slope of 3?

y = 3x + 5
y = 3x - 17
y = 3x - 5
y = 3x + 3

Answer 1

\[y-y_1=m(x-x_1)\]

Answer 2

point slope form:
y - 6 = 3(x - 1)
Distribute it:
y - 6 = 3x - 3
Solve for y and put into slope intercept form:
+ 6
y = 3x +3

Answer 3

y-6=3(x-1)
y=3x-3+6
y=3x+3