Question

how do i solve log2(x+4)-log2(x-3)=3

Answer 1

log2(x+4)-log2(x-3)=log2 2^3
log2 (x+4)/(x-3) = log2 8

Answer 2

\[log_2(x+4)-log_2(x-3)=3\]\[log_2\frac{(x+4)}{(x-3)}=log_22^3\]\[\frac{(x+4)}{(x-3)}=2^3\]\[(x+4)=8(x-3)\]Can you solve it?!

Answer 3

wait so it is (x+4)= 8x-24 or 5x

Answer 4

x+4 = 8x -24
7x =28
x=?

Answer 5

x=4

Answer 6

I think so.. but still you can check it again using your calculator !!