Question

Help me find the solution to 64^(x+3) = 42^(2x)

Answer 1

\(\Large \color{purple}{\rightarrow (2^6)^{x + 3} = (2^2)^{2x} }\)
\(\Large \color{purple}{\rightarrow 2^{6x + 18} = 2^{4x} }\)

Do you know how to solve further?

Answer 2

Just create an equation of the exponents when the bases are same.

\(\Large \color{purple}{\rightarrow 6x + 18 = 4x }\)
\(\Large \color{purple}{\rightarrow 18 = -2x }\)
\(\Large \color{purple}{\rightarrow x = -9 }\)