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Mathematics 21 Online
OpenStudy (anonymous):

simplify 9d^100

OpenStudy (anonymous):

how do u want me to solve it ???

OpenStudy (saifoo.khan):

It's already simplified.

OpenStudy (anonymous):

I dk

OpenStudy (anonymous):

no it is not

OpenStudy (saifoo.khan):

Yes it is.. Or else the question is incompelte.

OpenStudy (saifoo.khan):

incomplete*

OpenStudy (anonymous):

first we'll split the expression ...

OpenStudy (anonymous):

okay

OpenStudy (saifoo.khan):

and..?

OpenStudy (anonymous):

wait i've done these questions i need sometime to solve it

OpenStudy (saifoo.khan):

Lol annas it's already simplified.

OpenStudy (anonymous):

WELL I WILL BE RIGHT BACK WITH YOU I HAVE TO GO TO LUNCH

OpenStudy (anonymous):

@saifoo.khan dude its not simplified

OpenStudy (saifoo.khan):

Yes it is..

OpenStudy (anonymous):

SO WHAT IS IT THEN

OpenStudy (linna):

@annas \[\huge 3d^{20}\times 3d^{5}\neq 3d^{100} \]

OpenStudy (linna):

\[\LARGE 9d^{100}\]

OpenStudy (anonymous):

yeah i know sorry it was 9d^5^20

OpenStudy (anonymous):

thanks so much

OpenStudy (anonymous):

\[9d ^{5^{20}}\]

OpenStudy (anonymous):

can I have a medal

OpenStudy (anonymous):

sure here u go

OpenStudy (anonymous):

thanks solve (x+3)^2 =36

OpenStudy (anonymous):

x^2+6x+9=36 x^2+6X-27=0 put values of a,b,c in quadratic formula and you will get two roots ok

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