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whats the quadratic formula for x2-3x+1=0
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do u want the solutions?
iyess
x=1/2(3+sqrt5) :P
noo not right
and x=1/2(3-sqrt5)
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it is :P
i about to draw the answer choices
the answer should be x= 3+/-sqrt13/2
If ax^2 +bx +c =0 is the quadratic equation then the solution for x is x={-b±√(b^2 -4ac)} /(2a) Now for the given equation a=1, b=-3, c=-1 so x={-(-3)±√((-3)^2 -4(1)(-1))} /(2*1) ..={+3±√(9 +4))} /2 ..={3±√13}/2 So the solution set is {3+√13}/2, 3-√13}/2}
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